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show instructions question 4 (1 point) while traveling along a highway …

Question

show instructions question 4 (1 point) while traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. what is the automobile’s acceleration? (remember that a negative value indicates a slowing down.)
○ a 0.5m/s/s
○ b -0.83m/s/s
○ c -0.75m/s/s
○ d -0.90m/s/s

Explanation:

Step1: Recall the acceleration formula

The formula for acceleration \( a \) is \( a=\frac{v_f - v_i}{t} \), where \( v_f \) is the final velocity, \( v_i \) is the initial velocity, and \( t \) is the time.

Step2: Identify the values

Here, \( v_i = 24\space m/s \), \( v_f = 15\space m/s \), and \( t = 12\space s \).

Step3: Substitute the values into the formula

Substitute the values into the formula: \( a=\frac{15 - 24}{12} \).

Step4: Calculate the result

First, calculate the numerator: \( 15 - 24=-9 \). Then divide by the denominator: \( a=\frac{-9}{12}=- 0.75\space m/s^2 \). Wait, there is a typo in the options, maybe the negative sign is missed in option c? Wait, the options are: a. 0.5m/s/s, b. -0.85m/s/s, c. -0.75m/s/s, d. -0.90m/s/s. So the correct calculation gives \( a=\frac{15 - 24}{12}=\frac{-9}{12}=- 0.75\space m/s^2 \), so the correct option is c.

Answer:

c. -0.75m/s/s