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Question
- shonda is driving down the road. the force of gravity is pulling her car downward with 17,000 n, and the ground is pushing upward with 17,000 n. her car is producing a forward force of 880 n, and the air resistance is producing an 880 n force in the opposite direction. which statement describes the net force on shondas car at this moment?
there is a net force of 880 n forward
there is a net force of 35,760 n
there is a net force of 1760 n
there is zero net force.
Step1: Analyze vertical forces
The force of gravity \(F_g = 17000N\) (downward) and the normal force \(F_n=17000N\) (upward). Since \(F_g\) and \(F_n\) are equal in magnitude and opposite in direction, the net vertical force \(F_{net - vertical}=F_g - F_n=17000 - 17000=0N\).
Step2: Analyze horizontal forces
The forward force \(F_{forward}=880N\) and the air - resistance force \(F_{air - resistance}=880N\) (opposite to the forward direction). The net horizontal force \(F_{net - horizontal}=F_{forward}-F_{air - resistance}=880 - 880 = 0N\).
Step3: Calculate the net force
The net force \(F_{net}=\sqrt{F_{net - vertical}^2+F_{net - horizontal}^2}\). Since \(F_{net - vertical} = 0N\) and \(F_{net - horizontal}=0N\), \(F_{net}=0N\).
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There is zero net force.