Question

shila pushes a shopping cart of mass 5 kilograms with a force of 12 newtons across the floor of a grocery store. the floor exerts a frictional force of 7 newtons. what are the net force and acceleration of the cart?
net force = 19 newtons
acceleration = 3.8 meters/second²
net force = 5 newtons
acceleration = 1 meter/second²
net force = -5 newtons
acceleration = -1 meter/second²
net force = -5 newtons
acceleration = 1 meter/second²

Explanation:

Step1: Calculate net - force

The applied force $F_{applied}=12N$ and the frictional force $F_{friction}=7N$. The frictional force acts in the opposite direction of the applied force. The net - force $F_{net}$ is given by $F_{net}=F_{applied}-F_{friction}$.
$F_{net}=12 - 7=5N$

Step2: Calculate acceleration

According to Newton's second law $F = ma$, where $F$ is the net - force, $m$ is the mass and $a$ is the acceleration. We know $F_{net}=5N$ and $m = 5kg$. Rearranging the formula for acceleration gives $a=\frac{F_{net}}{m}$.
$a=\frac{5}{5}=1m/s^{2}$

Answer:

net force = 5 newtons, acceleration = 1 meter/second²