QUESTION IMAGE
Question
- sep use mathematics look at the data in the table. the frequencies are given in hz, which is defined as the number of waves per second. complete the table to show the speed of each wavelength of light.
- sep analyze data look at the wave speeds you calculated. what inference can you make from the data in the completed table?
enter your answer here.
- sep interpret data a student collects data on the light emitted when samples of two gases are heated. compare this data to that in the data table to identify each gas.
light emitted by gas x shows a wavelength of 5.06×10⁻⁷ m.
light emitted by gas y has a frequency of 4.98×10¹⁴ hz.
enter your answer here.
- sep use mathematics the complete emission spectrum of hydrogen includes four wavelengths. the data in the table includes three of these wavelengths. the missing fourth wavelength is 4.10×10⁻⁷ m. considering the formula given for the speed of a light wave and your answer to question 2, calculate the frequency of this wavelength of light.
enter your answer here.
Since the table with the initial data (wavelengths and frequencies) is not provided, we can't complete question 1 directly. However, we can explain the general approach for each question:
Question 1:
The formula for the speed of a light wave is \( v = \lambda f \), where \( v \) is the speed, \( \lambda \) is the wavelength, and \( f \) is the frequency. For each row in the table, you would multiply the given wavelength (\( \lambda \)) by the given frequency (\( f \)) to find the speed (\( v \)).
Question 2:
After calculating the speed for each wavelength, you would observe that the speed of light in a vacuum (or air, approximately) is constant, around \( 3.0 \times 10^8 \, \text{m/s} \). So the inference would be that the speed of light waves (in the same medium, like air or vacuum) is constant, regardless of their wavelength or frequency.
Question 3:
To identify the gases, you would:
- For gas X, use \( v = \lambda f \) to find its frequency (or if you have a table of known wavelengths/frequencies for gases, match the wavelength \( 5.06 \times 10^{-7} \, \text{m} \) to the table).
- For gas Y, use \( v = \lambda f \) to find its wavelength (or match the frequency \( 4.98 \times 10^{14} \, \text{Hz} \) to the table) and then identify the gas based on the known spectral lines.
Question 4:
Using the formula \( v = \lambda f \), we can solve for frequency \( f = \frac{v}{\lambda} \). From question 2, we know \( v \approx 3.0 \times 10^8 \, \text{m/s} \). Given \( \lambda = 4.10 \times 10^{-7} \, \text{m} \), we calculate:
\[
f = \frac{3.0 \times 10^8 \, \text{m/s}}{4.10 \times 10^{-7} \, \text{m}} \approx 7.32 \times 10^{14} \, \text{Hz}
\]
If you provide the table with the initial wavelengths and frequencies, we can help you complete question 1 and use that data for the subsequent questions.
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
Since the table with the initial data (wavelengths and frequencies) is not provided, we can't complete question 1 directly. However, we can explain the general approach for each question:
Question 1:
The formula for the speed of a light wave is \( v = \lambda f \), where \( v \) is the speed, \( \lambda \) is the wavelength, and \( f \) is the frequency. For each row in the table, you would multiply the given wavelength (\( \lambda \)) by the given frequency (\( f \)) to find the speed (\( v \)).
Question 2:
After calculating the speed for each wavelength, you would observe that the speed of light in a vacuum (or air, approximately) is constant, around \( 3.0 \times 10^8 \, \text{m/s} \). So the inference would be that the speed of light waves (in the same medium, like air or vacuum) is constant, regardless of their wavelength or frequency.
Question 3:
To identify the gases, you would:
- For gas X, use \( v = \lambda f \) to find its frequency (or if you have a table of known wavelengths/frequencies for gases, match the wavelength \( 5.06 \times 10^{-7} \, \text{m} \) to the table).
- For gas Y, use \( v = \lambda f \) to find its wavelength (or match the frequency \( 4.98 \times 10^{14} \, \text{Hz} \) to the table) and then identify the gas based on the known spectral lines.
Question 4:
Using the formula \( v = \lambda f \), we can solve for frequency \( f = \frac{v}{\lambda} \). From question 2, we know \( v \approx 3.0 \times 10^8 \, \text{m/s} \). Given \( \lambda = 4.10 \times 10^{-7} \, \text{m} \), we calculate:
\[
f = \frac{3.0 \times 10^8 \, \text{m/s}}{4.10 \times 10^{-7} \, \text{m}} \approx 7.32 \times 10^{14} \, \text{Hz}
\]
If you provide the table with the initial wavelengths and frequencies, we can help you complete question 1 and use that data for the subsequent questions.