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Question
semester 1 final exam study guide
chemistry
directions using the lesson notes for the topics below, fill in the study guide below to help you prepare for the semester 1 final exam on friday, december 12th. the bullet points that have bolded text are concepts, terms, or processes that you need to know for the final exam.
how to fill in study guide:
- if it is a vocabulary term, write the definition next to the term.
- if it is a calculation, solve the sample calculation and (optional) provide the steps on how to solve those types of problems.
- if it is an identification, write the keywords that will help you identify it easily.
unit 1 material:
- define:
- matter =
- mass =
- volume =
- density =
- water displacement method =
- convert between metric units (khdudcm)
- convert 2.5 km to m =
- convert 3.6 hl to cl =
- convert 250 mm to m =
| k | h | d | u | d | c | m |
| km | hm | dm | m | dm | cm | mm |
| kl | hl | dl | l | dl | cl | ml |
| kg | hg | dg | g | dg | cg | mg |
- convert between temperature units (k = °c + 273) (°c = k - 273)
- convert 25°c to k = ______ k
- convert 310 k to °c = ______ °c
Step1: Convert 2.5 km to m
The metric prefix "k" (kilo) means \(10^3\), so to convert kilometers to meters, we multiply by \(1000\) (since \(1\space km = 1000\space m\)).
\(2.5\space km\times1000 = 2500\space m\)
Step2: Convert 3.6 hL to cL
The metric prefix "h" (hecto) means \(10^2\) and "c" (centi) means \(10^{-2}\). To convert from hL to cL, we first convert hL to L (multiply by \(100\)) then L to cL (multiply by \(100\)), or use the total factor: \(1\space hL = 10^4\space cL\) (since \(10^2\times10^2 = 10^4\)).
\(3.6\space hL\times10^4 = 3.6\times10000 = 36000\space cL\)
Step3: Convert 250 mm to m
The metric prefix "m" (milli) means \(10^{-3}\), so to convert millimeters to meters, we divide by \(1000\) (since \(1\space m = 1000\space mm\)).
\(250\space mm\div1000 = 0.25\space m\)
Step4: Convert \(25^\circ C\) to K
Use the formula \(K = ^\circ C + 273\).
\(K = 25 + 273 = 298\space K\)
Step5: Convert 310 K to \(^\circ C\)
Use the formula \(^\circ C = K - 273\).
\(^\circ C = 310 - 273 = 37\space ^\circ C\)
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- Convert 2.5 km to m: \(\boldsymbol{2500\space m}\)
- Convert 3.6 hL to cL: \(\boldsymbol{36000\space cL}\)
- Convert 250 mm to m: \(\boldsymbol{0.25\space m}\)
- Convert \(25^\circ C\) to K: \(\boldsymbol{298\space K}\)
- Convert 310 K to \(^\circ C\): \(\boldsymbol{37\space ^\circ C}\)