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Question
select the correct answer.
what is the factored form of \\(24y^5 + 3y^2\\)?
\\(3y^2(2y - 1)(4y^2 + 2y + 1)\\)
\\(3y^2(2y + 1)(4y^2 - 2y + 1)\\)
\\((2y + 1)^2(4y^2 - 2y + 1)\\)
\\((2y - 1)^2(4y^2 + 2y + 1)\\)
Factor out the greatest common factor (GCF)
$$
24y^5 + 3y^2 = 3y^2(8y^3 + 1)
$$
Apply the sum of cubes formula
$$
LATEXBLOCK0
$$
Combine the factors
$$
24y^5 + 3y^2 = 3y^2(2y + 1)(4y^2 - 2y + 1)
$$
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- (A) \(3y^2(2y - 1)(4y^2 + 2y + 1)\)
- (B) \(3y^2(2y + 1)(4y^2 - 2y + 1)\) (Correct answer)
- (C) \((2y + 1)^2(4y^2 - 2y + 1)\)
- (D) \((2y - 1)^2(4y^2 + 2y + 1)\)