Question

select the correct answer from each drop-down menu.
on this map, oxford street is perpendicular to , and rosewood street is perpendicular to . assume that the street intersections form right angles.

Explanation:

Step1: Recall Perpendicular Definition

Perpendicular lines intersect at \(90^{\circ}\). In a grid - like street layout, horizontal and vertical streets are perpendicular.

Step2: Analyze Oxford Street's Orientation

Oxford Street is a vertical street (runs up - down). Horizontal streets (run left - right) are Waterloo St. and Rosewood St. So Oxford Street is perpendicular to Waterloo St. (and Rosewood St.).

Step3: Analyze Rosewood Street's Orientation

Rosewood Street is a horizontal street (runs left - right). Vertical streets (run up - down) are George St., Oak St., and Oxford St. So Rosewood Street is perpendicular to George St. (and Oak St., Oxford St.).

Answer:

For the first drop - down (Oxford Street is perpendicular to): Waterloo St. (and Rosewood St. as they are horizontal streets, and Oxford St. is vertical; also George St. and Oak St. are vertical, but perpendicular to horizontal streets. So possible correct ones are Waterloo St., Rosewood St.). For the second drop - down (Rosewood Street is perpendicular to): George St. (and Oak St. and Oxford St. as Rosewood St. is horizontal, and these are vertical streets).