Question

select the correct answer from each drop-down menu.
if a heterozygous male with the genotype ww is mated with a homozygous recessive female of genotype ww, there is a chance that 50% of the offspring will be heterozygous.

	w	w
w	ww	ww

if the heterozygous, ww, is crossed with a homozygous dominant, ww, then the probability of having a homozygous recessive offspring is

	w	w
w	ww	ww

drop - down with 0%, 50%, 100%

Explanation:

Step1: Analyze the Punnett square for Ww × WW

The Punnett square shows the possible genotypes of the offspring: WW (from W×W), Ww (from W×w), WW (from W×W), and Ww (from W×w).

Step2: Identify homozygous recessive genotypes

A homozygous recessive genotype would be ww (two recessive alleles). Looking at the Punnett square, none of the offspring genotypes are ww.

Step3: Calculate the probability

Since there are 0 out of 4 (or any number of offspring considered) with the ww genotype, the probability is 0%.

Answer:

0%