Question

the segment below is dilated by a scale factor of 4 to form \\(\overline{ef}\\). what is the measure of \\(\overline{ef}\\)?

answer attempt 2 out of 2

Explanation:

Step1: Recall dilation of a segment

When a segment is dilated by a scale factor \( k \), the length of the dilated segment is the original length multiplied by \( k \). Here, the original length of \( \overline{EF} \) is 23, and the scale factor is 4.

Step2: Calculate the length of \( \overline{E'F'} \)

The formula for the length of the dilated segment is \( \text{Length of } \overline{E'F'} = \text{Length of } \overline{EF} \times \text{scale factor} \). Substituting the values, we get \( 23 \times 4 = 92 \).

Answer:

92