Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

section 4: vitals conversion 1. convert 102.2°f to celsius → __ 2. conv…

Question

section 4: vitals conversion

  1. convert 102.2°f to celsius → __
  2. convert 38°c to fahrenheit → __
  3. a patient’s weight is 176 lbs. convert to kg → __

section 5: real-life case studies
case study 1: pediatric dosage
a 4-year-old child weighing 18 kg needs an antibiotic. the doctor prescribes 25 mg/kg/day divided into two doses. the medication is available as 100 mg/5 ml suspension.

  • total daily dose in mg? → __
  • how many ml per dose? → __
  • if first dose is at 0800, what is the military time for the second dose? → __

case study 2: iv infusion
a patient requires 1000 ml of 0.9% saline over 8 hours. drop factor: 15 gtt/ml.

  • flow rate in gtt/min? → __
  • if infusion starts at 0930, what time will it finish in military time? → __

case study 3: vitals & weight-based medication
patient weighs 154 lbs, needs medication dosed at 2 mg/kg. medication concentration: 10 mg/ml.

  • convert weight to kg → __
  • calculate total dose in mg → __
  • how many ml to administer? → __
  • if medication is given at 7:45 pm, what is the military time? → __

section 6: reflection

  • why is accuracy in medical math critical for patient safety?
  • give an example of a real-life scenario where incorrect calculations could lead to harm.

Explanation:

Section 4: Vitals Conversion
1. Convert \( 102.2^\circ\text{F} \) to Celsius

Step 1: Recall the formula for converting Fahrenheit to Celsius.

The formula is \( C = \frac{5}{9}(F - 32) \).

Step 2: Substitute \( F = 102.2 \) into the formula.

\( C = \frac{5}{9}(102.2 - 32) = \frac{5}{9}(70.2) \approx 39 \).

Step 1: Recall the formula for converting Celsius to Fahrenheit.

The formula is \( F = \frac{9}{5}C + 32 \).

Step 2: Substitute \( C = 38 \) into the formula.

\( F = \frac{9}{5}(38) + 32 = 68.4 + 32 = 100.4 \).

Step 1: Recall the conversion factor (1 lb ≈ 0.4536 kg).

Use the formula \( \text{kg} = \text{lbs} \times 0.4536 \).

Step 2: Substitute \( \text{lbs} = 176 \).

\( \text{kg} = 176 \times 0.4536 \approx 80 \) (or more precisely, \( 176 \times 0.4536 = 79.8336 \approx 80 \)).

Answer:

\( 39^\circ\text{C} \)

2. Convert \( 38^\circ\text{C} \) to Fahrenheit