Question

a sealed container can hold 0.325 l of gas at 1.00 atm and 293 k. use the ideal gas law, pv = nrt, to calculate the number of moles of gas the container can hold.
p = 1.00 atm v = 0.325 l
r = 0.0821 l·atm/mol·k t = 293 k
n = ?
? mol gas

Explanation:

Step1: Rearrange ideal gas law for n

$n = \frac{PV}{RT}$

Step2: Substitute given values

$n = \frac{(1.00\ \text{atm})(0.325\ \text{L})}{(0.0821\ \text{L·atm/mol·K})(293\ \text{K})}$

Step3: Calculate numerator and denominator

Numerator: $1.00 \times 0.325 = 0.325$
Denominator: $0.0821 \times 293 \approx 24.0553$

Step4: Compute n

$n \approx \frac{0.325}{24.0553} \approx 0.0135$

Answer:

0.0135 mol gas