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Question
if ( rv = 24 ), find ( xv ).
Step1: 重心性质
三角形的重心是三条中线的交点,且重心到顶点的距离是它到对边中点距离的\(2\)倍。
Step2: 计算\(XV\)
已知\(RV = 24\),因为\(RV\)是中线,\(X\)是重心,所以\(XV=\frac{1}{3}RV\)。
将\(RV = 24\)代入可得\(XV=\frac{1}{3}\times24 = 8\)。
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