Question

2 rotate point ( p(-2,-3) 90^{circ} mathrm{cw} ) using the rule ( (x, y)
ightarrow(y,-x) ) ( p^{prime}(quad, quad) )

Explanation:

Step1: Identify the values of \(x\) and \(y\)

Given the point \(P(-2,-3)\), here \(x = - 2\) and \(y=-3\).

Step2: Apply the rotation rule \((x,y)\to(y,-x)\)

Substitute \(x=-2\) and \(y = - 3\) into the rule.
For the \(x\) - coordinate of the new point: use the \(y\) - value of the original point. So it is \(y=-3\).
For the \(y\) - coordinate of the new point: use \(-x\). Since \(x=-2\), then \(-x=-(-2) = 2\).

Answer:

\(P'(-3,2)\)