Question

rotate $\triangle jkl$ $90^{circ}$ counterclockwise around the origin.

Explanation:

Step1: Find the coordinates of original points

Assume \( J=(2, - 2)\), \(K=(10,-2)\), \(L=(2,-8)\) (estimated from the graph). The rule for a \(90^{\circ}\) counter - clockwise rotation around the origin is \((x,y)\to(-y,x)\).

Step2: Apply the rotation rule to each point

• For \(J(2,-2)\):

Substitute \(x = 2\) and \(y=-2\) into the rule \((x,y)\to(-y,x)\). We get \(J'=(2,2)\).

• For \(K(10,-2)\):

Substitute \(x = 10\) and \(y =-2\) into the rule \((x,y)\to(-y,x)\). We get \(K'=(2,10)\).

• For \(L(2,-8)\):

Substitute \(x = 2\) and \(y=-8\) into the rule \((x,y)\to(-y,x)\). We get \(L'(8,2)\).

Answer:

The coordinates of the rotated triangle \(J'K'L'\) are \(J'(2,2)\), \(K'(2,10)\) and \(L'(8,2)\)