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a regular octagon has an apothem measuring 10 in. and a perimeter of 66…

Question

a regular octagon has an apothem measuring 10 in. and a perimeter of 66.3 in. what is the area of the octagon, rounded to the nearest square inch? 88 in.² 175 in.² 332 in.² 700 in.²

Explanation:

Step1: Recall the formula for the area of a regular polygon

The formula for the area \(A\) of a regular polygon is \(A=\frac{1}{2}\times a\times P\), where \(a\) is the apothem and \(P\) is the perimeter.

Step2: Substitute the given values into the formula

Given \(a = 10\) in and \(P=66.3\) in. Then \(A=\frac{1}{2}\times10\times66.3\).
First, calculate \(\frac{1}{2}\times10 = 5\).
Then, \(A=5\times66.3=331.5\).

Answer:

\(332\) in.\(^{2}\) (since \(331.5\approx332\) when rounded to the nearest square inch)