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with reference to the figure, match the angles and arcs to their measur…

Question

with reference to the figure, match the angles and arcs to their measures. ∠eob, 122°, ∠dfa, $widehat{ce}$, 114°, ∠oca, 124°, 58°, ∠cob

Explanation:

Step1: Find ∠OCA

Since AC is a tangent to the circle at C, OC is perpendicular to AC (tangent - radius property), so ∠OCA = 90°. Wait, no, maybe I misread. Wait, the angle at A is 114°, so the adjacent angle on the straight line: ∠OCA? Wait, no, let's find other angles. First, at point D, the angle is 124°, so the adjacent angle (linear pair) is 180 - 124 = 56°? Wait, maybe better to find ∠DFA.

Step2: Find ∠DFA

The sum of exterior angles of a triangle? Wait, the two tangent lines from F to the circle, so FE = FB (tangents from a point to a circle are equal), and OC is perpendicular to AC, OE perpendicular to FE. So quadrilateral OEFC and OBCF? Wait, maybe first find the angles at A and D. At A, the angle between tangent and secant? Wait, the angle at A: the straight line, so the angle adjacent to 114° is 180 - 114 = 66°? Wait, no, the figure has a triangle with vertices D, A, F. At D, angle is 124°, so the internal angle at D is 180 - 124 = 56°, at A, internal angle is 180 - 114 = 66°, so ∠DFA = 180 - 56 - 66 = 58°. So ∠DFA = 58°.

Step3: Find arc CE

The central angle for arc CE: since OE and OC are radii, ∠EOC. Wait, the tangents from F: ∠DFA = 58°, so the angle between tangents is 58°, so the central angle ∠EOB? Wait, no, the angle between two tangents is equal to 180° minus the central angle between the points of contact. So ∠DFA = 58°, so central angle ∠EOB = 180 - 58 = 122°? Wait, no, the formula is angle between tangents = 180° - central angle. So if ∠DFA = 58°, then central angle ∠EOB = 180 - 58 = 122°? Wait, maybe. Then arc CE: the measure of arc CE is equal to the central angle ∠EOC? Wait, maybe I made a mistake. Let's re - check.

Wait, at point A, the angle between tangent AC and line FA is 114°, so the angle between tangent and radius OC is 90°, so ∠OAC = 180 - 114 = 66°? No, OC is perpendicular to AC, so ∠OCA = 90°, so in triangle OAC, but maybe not. Wait, let's list the given angles and arcs:

We have ∠DFA = 58° (from step 2: 180 - (180 - 124) - (180 - 114) = 180 - 56 - 66 = 58°).

Then ∠EOB: the central angle. The angle between tangents ∠DFA = 58°, so the central angle ∠EOB = 180 - 58 = 122° (because the angle between two tangents is supplementary to the central angle between the points of contact).

Arc CE: the measure of arc CE is equal to the central angle ∠EOC. Wait, but we also have ∠COB. Wait, maybe ∠COB: since AC and BC are tangents? Wait, no, AC is tangent at C, AB is tangent at B? Wait, the circle is tangent to AC at C, to AE at E, and to AB at B? Wait, maybe OC is perpendicular to AC, OB is perpendicular to AB, so ∠OCA = 90°, ∠OBA = 90°. Then in quadrilateral O C A B, ∠CAB = 180 - 114 = 66°, so ∠COB = 180 - 66 = 114° (since sum of angles in quadrilateral is 360°, 90 + 90 + 66 + ∠COB = 360 → ∠COB = 114°).

Then arc CE: the central angle ∠EOC. We know that ∠EOB = 122°, ∠COB = 114°, so ∠EOC = 360 - 122 - 114 = 124°? Wait, no, that can't be. Wait, maybe the circle is a circle with center O, and CE, CB are arcs. Wait, maybe I messed up. Let's try again.

  1. ∠DFA: as calculated, 58°, so ∠DFA ↔ 58°.
  1. ∠EOB: 122°, so ∠EOB ↔ 122°.
  1. ∠COB: 114°, so ∠COB ↔ 114°.
  1. Arc CE: the central angle for arc CE is ∠EOC. Since ∠EOB = 122°, ∠COB = 114°, no, that's more than 180. Wait, maybe the angle at D is 124°, so the arc DE? No, maybe the measure of arc CE is 124°? Wait, the angle at D is 124°, which is an external angle, equal to the measure of the arc CE (by the tangent - secant angle theorem: the measure of an angle formed by a tangent and a secant is half the difference of the measures of the intercepted arcs…

Answer:

∠DFA ↔ 58°
∠EOB ↔ 122°
∠COB ↔ 114°
$\widehat{CE}$ ↔ 124°