Question

rectangle written as a product (length)(wid bel its length and width. then write an equ written as the sum of the parts. b. $2x(x + 5)$

Explanation:

Step1: Identify length and width

The expression \(2x(x + 5)\) is in the form of length \(\times\) width. We can consider the length as \(2x\) and the width as \((x + 5)\).

Step2: Expand the product

Using the distributive property \(a(b + c)=ab+ac\), where \(a = 2x\), \(b=x\), and \(c = 5\).

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Answer:

If we consider the rectangle with length \(l = 2x\) and width \(w=(x + 5)\), then the area written as a sum of parts is \(2x^{2}+10x\)