Question

quiz_chap 5_periodic table
based on electron configuration, which atom has the greatest radius?
○ ne3s²3p⁵
○ ne3s²3p⁴
○ ar4s²
○ ne3s²3p³

Explanation:

• First, identify the elements from their electron configurations.
• \([Ne]3s^{2}3p^{5}\) is chlorine (\(Cl\)).
• \([Ne]3s^{2}3p^{4}\) is sulfur (\(S\)).
• \([Ar]4s^{2}\) is calcium (\(Ca\)).
• \([Ne]3s^{2}3p^{3}\) is phosphorus (\(P\)).
• Then, recall the trend in atomic radius: Atomic radius increases down a group and decreases across a period.
• \(Ca\) is in period 4, while \(Cl\), \(S\), and \(P\) are in period 3. Since \(Ca\) has an additional electron shell (due to being in a higher period), it will have a larger radius than the elements in period 3.

Answer:

\([Ar]4s^{2}\)