Question

question which of these contexts describes a situation that is likely? answer rolling a number less than or equal to 5 on a standard six - sided die, numbered from 1 to 6. spinning a spinner divided into four equal - sized sections colored red/green/yellow/blue and landing on white. winning a raffle that sold a total of 100 tickets if you bought 1 ticket. reaching into a bag full of 15 strawberry chews and 5 cherry chews without looking and pulling out an orange chew.

Explanation:

Step1: Calculate probabilities for each option

• Rolling a number less than or equal to 5 on a standard six - sided die:

The sample space \(n(S)=6\) (the numbers \(1,2,3,4,5,6\)). The favorable outcomes \(n(A) = 5\) (the numbers \(1,2,3,4,5\)). The probability \(P(A)=\frac{n(A)}{n(S)}=\frac{5}{6}\approx0.83\)

• Spinning a spinner divided into four equal - sized sections colored red/green/yellow/blue and landing on white:

The sample space \(n(S) = 4\) (red, green, yellow, blue). The number of favorable outcomes \(n(A)=0\) (there is no white section). The probability \(P(A)=\frac{n(A)}{n(S)} = 0\)

• Winning a raffle that sold a total of 100 tickets if you bought 1 ticket:

The sample space \(n(S)=100\). The number of favorable outcomes \(n(A) = 1\). The probability \(P(A)=\frac{n(A)}{n(S)}=\frac{1}{100}=0.01\)

• Reaching into a bag full of 15 strawberry chews and 5 cherry chews without looking and pulling out an orange chew:

The sample space \(n(S)=15 + 5=20\). The number of favorable outcomes \(n(A)=0\) (there are no orange chews). The probability \(P(A)=\frac{n(A)}{n(S)}=0\)

Answer:

Rolling a number less than or equal to 5 on a standard six - sided die.