Question

question: two sides of a parallelogram are 9.3 feet and 4.4 feet. the measure of the angle between these sides is 53°. find the area of the parallelogram to the nearest 10th of a square foot. answer: attempt 1 out of 2 ft² submit answer watch video show examples

Explanation:

Step1: Recall area formula for parallelogram

The area formula of a parallelogram is $A = ab\sin\theta$, where $a$ and $b$ are the lengths of two - adjacent sides and $\theta$ is the included angle between them.

Step2: Substitute given values

We are given $a = 9.3$ feet, $b = 4.4$ feet, and $\theta=53^{\circ}$. First, find $\sin(53^{\circ})\approx0.7986$. Then $A = 9.3\times4.4\times\sin(53^{\circ})$.

Step3: Calculate the area

$A=9.3\times4.4\times0.7986 = 9.3\times3.51384\approx32.7$ square feet.

Answer:

$32.7$ square feet