Question

question 4.
h₂o
a. ○ sp
b. ○ sp²
c. ○ sp³
d. ○ sp³d
e. ○ sp³d²
question 5
brf₃
a. ○ sp
b. ○ sp²
c. ○ sp³
d. ○ sp³d
e. ○ sp³d²
question 6

Explanation:

Question 4:

Step1: Calculate the steric number of \(H_2O\)

The steric number \(SN=\) number of bonding pairs + number of lone pairs. For \(H_2O\), the central atom is \(O\). The number of bonding pairs \(= 2\) (two \(O - H\) bonds), and the number of lone pairs \(= 2\). So \(SN=2 + 2=4\).

Step2: Determine the hybridization

If \(SN = 4\), the hybridization is \(sp^{3}\).

Question 5:

Step1: Calculate the steric number of \(BrF_3\)

The central atom is \(Br\). The number of bonding pairs \(= 3\) (three \(Br - F\) bonds). The number of lone pairs: \(Br\) has \(7\) valence electrons. After forming \(3\) bonds (using \(3\) electrons), there are \(7-3 = 4\) electrons left, which is \(2\) lone pairs. So \(SN=3 + 2=5\).

Step2: Determine the hybridization

If \(SN = 5\), the hybridization is \(sp^{3}d\).

Answer:

Question 4: C. \(sp^{3}\)
Question 5: D. \(sp^{3}d\)