Question

question
solve the following quadratic equation for all values of x in simplest form:
4 + 8x² = 7

Explanation:

Step1: Isolate the $x^2$ term

Subtract 4 from both sides:
$3x^2 = 7 - 4$
$3x^2 = 3$

Step2: Solve for $x^2$

Divide both sides by 3:
$x^2 = \frac{3}{3}$
$x^2 = 1$

Step3: Solve for $x$

Take square root of both sides:
$x = \pm\sqrt{1}$
$x = \pm1$

Answer:

$x = 1$ and $x = -1$