Question

question
solve for all values of $x$ by factoring.
$x^{2}-4x - 59=-4x + 5$
answer attempt 1 out of 2
+ additional solution - no solution
$x=$

Explanation:

Step1: Rearrange the equation

Add $4x$ to both sides and subtract 5 from both sides of the equation $x^{2}-4x - 59=-4x + 5$. We get $x^{2}-4x+4x-59 - 5=0$, which simplifies to $x^{2}-64 = 0$.

Step2: Factor the left - hand side

Use the difference of squares formula $a^{2}-b^{2}=(a + b)(a - b)$. Here $a=x$ and $b = 8$, so $x^{2}-64=(x + 8)(x - 8)=0$.

Step3: Solve for $x$

Set each factor equal to zero. If $x+8=0$, then $x=-8$. If $x - 8=0$, then $x = 8$.

Answer:

$x = 8,x=-8$