Question

question 8
a sample of argon gas is collected in a cylinder with a movable piston as seen in the diagram below. the initial measurements of the gas are given. the piston moves upward and the volume expands to 520.0 ml. what is the new pressure of the sample of gas, assuming that the temperature remains constant?
volume = 350.0 ml
pressure = 1.52 atm
temperature = 25.0 °c
2.26 atm
0.0409 atm
1.02 atm
25.6 atm

Explanation:

Step1: Recall Boyle's Law

Boyle's Law states that \(P_1V_1 = P_2V_2\) (for a gas at constant temperature).

Step2: Identify the given values

\(P_1=1.52\space atm\), \(V_1 = 350.0\space mL\), \(V_2=520.0\space mL\). We need to find \(P_2\).

Step3: Rearrange the formula to solve for \(P_2\)

\(P_2=\frac{P_1V_1}{V_2}\)

Step4: Substitute the values into the formula

\(P_2=\frac{1.52\space atm\times350.0\space mL}{520.0\space mL}\)
\(P_2=\frac{532}{520}\space atm\)
\(P_2 = 1.02\space atm\)

Answer:

1.02 atm