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question 3 (2 points) what is the concentration of a 5.00 m solution af…

Question

question 3 (2 points)
what is the concentration of a 5.00 m solution after a 1:10 dilution?
there are 4 variables in the dilution equation. the problem will give three, then you
solve for the missing variable. here the dilution factor of 1:10 represents two, the
ratio of ( v_c/v_d ) so, we either multiply 5.00 m by the ratio to get
( 5.00 m(\frac{v_c}{v_d}) = 5.00 m(\frac{1}{10}) = 0.500 m )
or, we divide 5.00 m by the ratio to get
( 5.00 m(\frac{v_d}{v_c}) = 5.00 m(\frac{10}{1}) = 50.0 m )
the only answer that makes sense is 1
a. 0.500 m
b. 50.0 m

Explanation:

Step1: Understand the dilution concept

When diluting a solution, the amount of solute remains the same. The dilution formula can be thought of in terms of the ratio of the initial volume (\(V_c\)) to the final volume (\(V_d\)). A \(1:10\) dilution means \(V_d = 10V_c\).

Step2: Apply the dilution formula

The formula for dilution in terms of concentration (\(C\)) and volume (\(V\)) is \(C_1V_1=C_2V_2\). Here, \(C_1 = 5.00\space M\), and \(\frac{V_1}{V_2}=\frac{1}{10}\). We can rewrite the formula for \(C_2\) as \(C_2 = C_1\times\frac{V_1}{V_2}\).
Substitute the values: \(C_2=5.00\space M\times\frac{1}{10}\)

Answer:

A. \(0.500\space M\)