Question

question 2 (5 points)
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if the mass defect for a radionuclide is -8.7839×10 - 30 kg, whats the binding energy per atom?
a) -7.8944×10 - 13 kj/atom
b) 7.8944×10 - 13 j/atom
c) -7.8944×10 - 13 j/atom
d) -4.76×1011 j/atom

Explanation:

Step1: Recall Einstein's mass - energy equivalence formula

The formula is $E = \Delta mc^{2}$, where $E$ is the energy, $\Delta m$ is the mass defect, and $c$ is the speed of light in a vacuum with a value of $c = 3.0\times10^{8}\ m/s$.

Step2: Substitute the given values into the formula

We are given $\Delta m=- 8.7839\times10^{-30}\ kg$ and $c = 3.0\times10^{8}\ m/s$.
Substitute these values into $E=\Delta mc^{2}$:

$$
LATEXBLOCK0
$$

Rounding to a reasonable number of significant figures, we get $E\approx - 7.8944\times10^{-13}\ J/atom$

Answer:

C) $-7.8944\times10^{-13}\ J/atom$