Question

question 4 (5 points)
find ( 6 sin 30 ^ { 0 } + 7 \tan 45 ^ { 0 } - 4 cos 60 ^ { 0 } )
1
8
7
( 10 - 2 sqrt { 3 } )

Explanation:

Step1: Substitute trigonometric values

We know that \(\sin30^{\circ}=\frac{1}{2}\), \(\tan45^{\circ} = 1\), \(\cos60^{\circ}=\frac{1}{2}\).
Substitute these values into the expression \(6\sin30^{\circ}+7\tan45^{\circ}-4\cos60^{\circ}\):
\(6\times\frac{1}{2}+7\times1 - 4\times\frac{1}{2}\)

Step2: Perform multiplications

Calculate each product:
\(6\times\frac{1}{2}=3\), \(7\times1 = 7\), \(4\times\frac{1}{2}=2\)
The expression becomes \(3 + 7-2\)

Step3: Perform additions and subtractions

First, \(3+7=10\), then \(10 - 2=8\)

Answer:

8