Question

question 2 points 3

find \\(-8n\\) if \\(n = \

$$\begin{bmatrix} 1 & -1 & 2 & -2 & -3 \\\\ 3 & -4 & 4 & -5 & 5 \\\\ 6 & -6 & 7 & -7 & 8 \\\\ -8 & 9 & -9 & 0 & 10 \\\\ -10 & -20 & 20 & -30 & 30 \\end{bmatrix}$$

\\).

\\(\bigcirc\\) \\(\

$$\begin{bmatrix} 8 & -8 & 16 & -16 & -24 \\\\ 24 & -32 & 32 & -40 & 40 \\\\ 48 & -48 & 56 & -56 & 64 \\\\ -64 & 72 & -72 & 0 & 80 \\\\ -80 & -160 & 160 & -240 & 240 \\end{bmatrix}$$

\\)

\\(\bigcirc\\) \\(\

$$\begin{bmatrix} -8 & 8 & -16 & 16 & 24 \\\\ -24 & 32 & -32 & 40 & -40 \\\\ -48 & 48 & -56 & 56 & -64 \\end{bmatrix}$$

\\)

Explanation:

Identify the given matrix and scalar

Using the Scalar Multiplication knowledge point

$$ N =
LATEXBLOCK0
, \quad k = -8 $$

Multiply each element by the scalar

Using the Scalar Multiplication knowledge point

$$ -8N =
LATEXBLOCK1
$$

Simplify the resulting matrix elements

Using the Scalar Multiplication knowledge point

$$ -8N =
LATEXBLOCK2
$$

Answer:

• (A) \(

$$\begin{bmatrix} 8 & -8 & 16 & -16 & -24 \\ 24 & -32 & 32 & -40 & 40 \\ 48 & -48 & 56 & -56 & 64 \\ -64 & 72 & -72 & 0 & 80 \\ -80 & -160 & 160 & -240 & 240 \end{bmatrix}$$

\)

• **(B) \(

$$\begin{bmatrix} -8 & 8 & -16 & 16 & 24 \\ -24 & 32 & -32 & 40 & -40 \\ -48 & 48 & -56 & 56 & -64 \\ 64 & -72 & 72 & 0 & -80 \\ 80 & 160 & -160 & 240 & -240 \end{bmatrix}$$

\) (Correct answer)**