Question

question 6 (3 points) (01.10 mc) a position versus time graph is shown below. position vs. time graph use the graph to determine the instantaneous velocity in m/s of the object at 3 seconds. a 4 m/s north b 3 m/s north c 1.3 m/s north d 0 m/s north

Explanation:

Step1: Recall velocity from position - time graph

The instantaneous velocity at a point on a position - time graph is given by the slope of the tangent to the graph at that point. For a position - time graph, when the graph is a horizontal line (constant position), the slope is zero.

Step2: Analyze the graph at \(t = 3\) seconds

Looking at the position - time graph, at \(t=3\) seconds, the graph is a horizontal line (from \(t = 1\) second to \(t = 4\) seconds approximately, the position does not change). The slope of a horizontal line is \(m=\frac{\Delta y}{\Delta x}\), where \(\Delta y\) (change in position) is \(0\) (since position is constant) and \(\Delta x\) (change in time) is non - zero. So the slope (instantaneous velocity) is \(v=\frac{\Delta x}{\Delta t}=0\) (because \(\Delta x = 0\)).

Answer:

d. 0 m/s north