Question

question 3 (1 point)
using the appropriate special triangle, determine θ if 0° ≤ θ ≤ 90° for cosθ = √3/2.

a) 90°
b) 60°
c) 30°
d) 45°

Explanation:

Step1: Recall special - angle cosine values

We know that for a \(30^{\circ}-60^{\circ}-90^{\circ}\) triangle, \(\cos30^{\circ}=\frac{\sqrt{3}}{2}\), \(\cos45^{\circ}=\frac{\sqrt{2}}{2}\), \(\cos60^{\circ}=\frac{1}{2}\), \(\cos90^{\circ} = 0\).

Answer:

C. \(30^{\circ}\)