Question

question 8 (1 point)
a leaky faucet drips 40 times in 30.0s. what is the frequency of the dripping?

a) 0.93 hz

b) 1.7 hz

c) 0.75 hz

d) 1.3 hz

e) 0.63 hz

f) 1.6 hz

Explanation:

Step1: Recall Frequency Formula

Frequency \( f \) is defined as the number of events (drips, in this case) per unit time. The formula is \( f = \frac{N}{t} \), where \( N \) is the number of events and \( t \) is the time.

Step2: Identify Values

Here, \( N = 40 \) (number of drips) and \( t = 30.0 \, \text{s} \) (time).

Step3: Calculate Frequency

Substitute the values into the formula: \( f = \frac{40}{30.0} \approx 1.333\ldots \, \text{Hz} \). Wait, no, wait—wait, 40 divided by 30? Wait, no, 40 drips in 30 seconds. Wait, 40/30 is approximately 1.333, but looking at the options, d) is 1.3 Hz, which is the closest. Wait, did I miscalculate? Wait, 40 divided by 30: 40 ÷ 30 = 1.333..., which rounds to 1.3 Hz (option d) or maybe I made a mistake. Wait, no, let's check again. Wait, frequency is cycles per second. So 40 drips in 30 seconds, so per second, it's 40/30 ≈ 1.333 Hz, which is approximately 1.3 Hz (option d) or maybe 1.3 is the closest. Wait, the options: d) 1.3 Hz. So the calculation is \( f = \frac{40}{30.0} \approx 1.3 \, \text{Hz} \).

Answer:

d) 1.3 Hz