Question

question
identify whether the graph of the function $f(x)$ shown below is even, odd, or neither.

answer attempt 1 out of 3
the graph is because

Explanation:

Step1: Recall symmetry rules

A function is even if its graph is symmetric about the \( y \)-axis (\( f(-x)=f(x) \)), and odd if symmetric about the origin (\( f(-x)=-f(x) \)).

Step2: Analyze the graph

Check the graph's symmetry. The graph is mirrored over the \( y \)-axis: for every point \( (x,y) \), \( (-x,y) \) also exists (e.g., left and right of \( y \)-axis have matching shapes/values).

Answer:

The graph is even because it is symmetric about the \( y \)-axis (satisfies \( f(-x) = f(x) \)).