Question

question
express in simplest radical form.
\sqrt{48}

Explanation:

Step1: Factor the radicand

Factor 48 into a product of a perfect square and another number: $48 = 16\times3$, where 16 is a perfect square.

Step2: Apply the square - root property

Using the property $\sqrt{ab}=\sqrt{a}\times\sqrt{b}$ (for $a\geq0,b\geq0$), we have $\sqrt{48}=\sqrt{16\times3}=\sqrt{16}\times\sqrt{3}$.
Since $\sqrt{16} = 4$, then $\sqrt{48}=4\sqrt{3}$.

Answer:

$4\sqrt{3}$