Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

question 4. drag the appropriate terms or numbers into the correct spac…

Question

question 4. drag the appropriate terms or numbers into the correct spaces in the table below:

ion type | number of electrons | electron configuration of ion | noble gas configuration achieved
--- | --- | --- | ---
na⁺ | | |
n³⁻ | | |
ca²⁺ | | |
br⁻ | | |
al³⁺ | | |

various numbers and electron configurations as options below the table

Explanation:

Step1: Analyze $\ce{Na+}$

Sodium (Na) has an atomic number of 11, so a neutral Na atom has 11 electrons. $\ce{Na+}$ is formed by losing 1 electron, so the number of electrons is $11 - 1 = 10$. The electron configuration of $\ce{Na+}$ is $1s^2 2s^2 2p^6$ (since it loses the 3s¹ electron), and this matches the noble gas configuration of neon (Ne).

Step2: Analyze $\ce{N^{3-}}$

Nitrogen (N) has an atomic number of 7, so a neutral N atom has 7 electrons. $\ce{N^{3-}}$ is formed by gaining 3 electrons, so the number of electrons is $7 + 3 = 10$. The electron configuration is $1s^2 2s^2 2p^6$, which is the noble gas configuration of neon (Ne).

Step3: Analyze $\ce{Ca^{2+}}$

Calcium (Ca) has an atomic number of 20, so a neutral Ca atom has 20 electrons. $\ce{Ca^{2+}}$ is formed by losing 2 electrons, so the number of electrons is $20 - 2 = 18$. The electron configuration is $1s^2 2s^2 2p^6 3s^2 3p^6$ (losing the 4s² electrons), which is the noble gas configuration of argon (Ar).

Step4: Analyze $\ce{Br-}$

Bromine (Br) has an atomic number of 35, so a neutral Br atom has 35 electrons. $\ce{Br-}$ is formed by gaining 1 electron, so the number of electrons is $35 + 1 = 36$. The electron configuration is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6$, which is the noble gas configuration of krypton (Kr).

Step5: Analyze $\ce{Al^{3+}}$

Aluminum (Al) has an atomic number of 13, so a neutral Al atom has 13 electrons. $\ce{Al^{3+}}$ is formed by losing 3 electrons, so the number of electrons is $13 - 3 = 10$. The electron configuration is $1s^2 2s^2 2p^6$, which is the noble gas configuration of neon (Ne).

Filling the Table:

Ion TypeNumber of ElectronsElectron Configuration of IonNoble Gas Configuration Achieved
$\ce{N^{3-}}$10$1s^2 2s^2 2p^6$neon (Ne)
$\ce{Ca^{2+}}$18$1s^2 2s^2 2p^6 3s^2 3p^6$argon (Ar)
$\ce{Br-}$36$1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6$krypton (Kr)
$\ce{Al^{3+}}$10$1s^2 2s^2 2p^6$neon (Ne)

Answer:

The table is filled as shown above with the respective number of electrons, electron configurations, and noble gas configurations for each ion.