Question

question 4
a constant force of 25 n is applied as shown to a block which undergoes a displacement of 7.5 m to the right along a frictionless surface while the force acts. what is the work done by the force?
+160 j
-160 j
+94 j
zero joules
-94 j

Explanation:

Step1: Recall the work - formula

The formula for work done by a force is \(W=\vec{F}\cdot\vec{s}=Fs\cos\theta\), where \(F\) is the magnitude of the force, \(s\) is the magnitude of the displacement, and \(\theta\) is the angle between the force and the displacement vectors.
Given \(F = 25\space N\), \(s=7.5\space m\), and \(\theta = 180^{\circ}- 30^{\circ}=150^{\circ}\)

Step2: Calculate the work

Substitute the values into the formula:

$$
LATEXBLOCK0
$$

Answer:

-160 J