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question 4 of 40
in triangle abc, (m\angle a = 45^{\circ}), (m\angle b = 40^{\circ}), and (a = 7). which equation should you solve to find (b)?
a. (\frac{\sin 45^{\circ}}{7} = \frac{\sin 40^{\circ}}{b})
b. (b^2 = 7^2 - 2(7)b\cos 40^{\circ})
c. (\frac{\cos 45^{\circ}}{7} = \frac{\cos 40^{\circ}}{b})
d. (\frac{\sin 45^{\circ}}{b} = \frac{\sin 40^{\circ}}{7})
State the Law of Sines
$$
\frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c}
$$
Substitute the given values
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- (A) \(\frac{\sin45^\circ}{7} = \frac{\sin40^\circ}{b}\) (Correct answer)
- (B) \(b^2 = 7^2 - 2(7)b\cos40^\circ\)
- (C) \(\frac{\cos45^\circ}{7} = \frac{\cos40^\circ}{b}\)
- (D) \(\frac{\sin45^\circ}{b} = \frac{\sin40^\circ}{7}\)