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Question
question 27 of 40
solve \\(\frac{x}{4} - 8 = y\\) for \\(x\\).
\\(\bigcirc\\) a. \\(x = 4y - 32\\)
\\(\bigcirc\\) b. \\(x = \frac{1}{4}y - 2\\)
\\(\bigcirc\\) c. \\(x = 4y + 32\\)
\\(\bigcirc\\) d. \\(x = \frac{1}{4}y + 2\\)
Step1: Add 8 to both sides
$\frac{x}{4} - 8 + 8 = y + 8$ → $\frac{x}{4} = y + 8$
Step2: Multiply by 4
$\frac{x}{4} \times 4 = (y + 8) \times 4$ → $x = 4y + 32$
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C. $x = 4y + 32$