Question

question 23
a child pulls a sled along frictionless snow with a rope at an angle θ = 38°. the child pulls with a force of f = 25 n and the rider and sled have a combined mass of 45 kg.
what is the horizontal component of the force f?
options: 17 n, 12 n, 15 n, 20 n

Explanation:

Step1: Recall force component formula

The horizontal component of a force \( F \) at an angle \( \theta \) is given by \( F_x = F \cos\theta \).

Step2: Substitute values

Given \( F = 25 \, \text{N} \) and \( \theta = 38^\circ \), we calculate \( \cos(38^\circ) \approx 0.7880 \). Then \( F_x = 25 \times 0.7880 \approx 19.7 \, \text{N} \), which is approximately \( 20 \, \text{N} \).

Answer:

20 N