Question

question 19 (4 points)
how many mg in 9.900 x 10^(-6) tg? note, this is set up as a two - step problem.
the intermediate answer is numerically 1 and the units are 2.
the final answer is numerically 3 and the units are 4.
a. 9.900 x 10^(-6) b. 9.900 x 10^6 c. 9.900 x 10^(-12) d. 9.900 x 10^12
e. 9.900 x 10^0 f. 9.900 x 10^(-9) g. 9.900 x 10^9 h. 9.900 x 10^(-3)
i. 9.900 x 10^3 j. g k. mg l. tg m. no units

Explanation:

Step1: Convert Tg to g

We know that $1\ Tg = 10^{12}\ g$. So for $9.900\times 10^{-6}\ Tg$, we have $9.900\times 10^{-6}\times10^{12}\ g=9.900\times 10^{6}\ g$. The intermediate - answer numerically is $9.900\times 10^{6}$ and the units are $g$.

Step2: Convert g to Mg

We know that $1\ Mg = 10^{6}\ g$. So, $\frac{9.900\times 10^{6}\ g}{10^{6}\ g/Mg}=9.900\times 10^{0}\ Mg$. The final answer numerically is $9.900\times 10^{0}$ and the units are $Mg$.

Answer:

1. B. $9.900\times 10^{6}$
2. J. g
3. E. $9.900\times 10^{0}$
4. K. Mg