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Question
question 16 (mandatory) (1 point) if 3^{x^{2}+1}=243, then x is equal to a) 5 or 0 b) 4 or -4 c) 2 or -2 d) 2
Step1: Rewrite 243 as a power of 3
Since \(243 = 3^5\), the equation \(3^{x^{2}+1}=243\) becomes \(3^{x^{2}+1}=3^5\).
Step2: Equate the exponents
If \(a^m=a^n\), then \(m = n\). So, \(x^{2}+1 = 5\).
Step3: Solve for \(x\)
Subtract 1 from both sides: \(x^{2}=5 - 1=4\). Then take the square - root of both sides. \(x=\pm\sqrt{4}=\pm2\).
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C. 2 or - 2