Question

question 15
1 pts
a silver picture frame displaces 0.454 l of water and has a mass of 2.78 kg. calculate the density of the silver in g/cm³.
note: 1 ml = 1 cm³
6.12 g/cm³
8.62 g/cm³
19.3 g/cm³
1.31 g/cm³
question 16
1 pts
the density of liquid gold (au) is 19.3 g/cm³.
if given a volume of 450 ml of this liquid, what is the mass?
8685 g
7962 g
8700 g
9000 g

Explanation:

Question 15

Step1: Convert mass to grams

Since 1 kg = 1000 g, then 2.78 kg = 2.78×1000 = 2780 g.

Step2: Convert volume to cubic - centimeters

Since 1 L = 1000 mL and 1 mL = 1 cm³, then 0.454 L = 0.454×1000 = 454 cm³.

Step3: Calculate density

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume. Substituting $m = 2780$ g and $V = 454$ cm³, we get $
ho=\frac{2780}{454}\approx6.12$ g/cm³.

Step1: Convert volume to cubic - centimeters

Since 1 mL = 1 cm³, a volume of 450 mL is equal to 450 cm³.

Step2: Use the density formula to find mass

The density formula is $
ho=\frac{m}{V}$, which can be rewritten as $m=
ho V$. Given $
ho = 19.3$ g/cm³ and $V = 450$ cm³, then $m=19.3\times450 = 8685$ g.

Answer:

6.12 g/cm³

Question 16