Question

question 13
1 pts
which combination will produce a precipitate?
naoh (aq) and hcl (aq)
nac₂h₃o₂ (aq) and hcl (aq)
agno₃(aq) and ca(c₂h₃o₂)₂ (aq)
naf (aq) and hcl (aq)
koh (aq) and mg(no₃)₂ (aq)
question 14
1 pts
the net ionic equation for the reaction between aqueous sulfuric acid and aqueous sodium hydroxide is ________.
2h⁺ (aq) + so₄²⁻ (aq) + 2na⁺ (aq) + 2oh⁻ (aq) → 2h₂o (l) + 2na⁺ (aq) + so₄²⁻ (aq)
h⁺ (aq) + hso₄⁻ (aq) + 2na⁺ (aq) + 2oh⁻ (aq) → 2h₂o (l) + 2na⁺ (aq) + so₄²⁻ (aq)
so₄²⁻ (aq) + 2na⁺ (aq) → 2na⁺ (aq) + so₄²⁻ (aq)
h⁺ (aq) + hso₄⁻ (aq) + 2oh⁻ (aq) → 2h₂o (l) + so₄²⁻ (aq)
h⁺ (aq) + oh⁻ (aq) → h₂o(l)

Explanation:

Question 13

Check each option:

• Option 1: \(NaOH(aq)\) and \(HCl(aq)\)

This is an acid - base neutralization reaction. The reaction is \(NaOH(aq)+HCl(aq)
ightarrow NaCl(aq)+H_2O(l)\). \(NaCl\) is soluble in water, so no precipitate is formed.

• Option 2: \(NaC_2H_3O_2(aq)\) and \(HCl(aq)\)

The reaction is \(NaC_2H_3O_2(aq)+HCl(aq)
ightarrow NaCl(aq)+HC_2H_3O_2(aq)\). Both \(NaCl\) and \(HC_2H_3O_2\) are soluble in water, so no precipitate is formed.

• Option 3: \(AgNO_3(aq)\) and \(Ca(C_2H_3O_2)_2(aq)\)

The possible reaction is \(2AgNO_3(aq)+Ca(C_2H_3O_2)_2(aq)
ightarrow 2AgC_2H_3O_2(aq)+Ca(NO_3)_2(aq)\). \(AgC_2H_3O_2\) and \(Ca(NO_3)_2\) are soluble in water, so no precipitate is formed.

• Option 4: \(NaF(aq)\) and \(HCl(aq)\)

The reaction is \(NaF(aq)+HCl(aq)
ightarrow NaCl(aq)+HF(aq)\). \(NaCl\) and \(HF\) are soluble in water, so no precipitate is formed.

• Option 5: \(KOH(aq)\) and \(Mg(NO_3)_2(aq)\)

The reaction is \(2KOH(aq)+Mg(NO_3)_2(aq)
ightarrow 2KNO_3(aq)+Mg(OH)_2(s)\). \(Mg(OH)_2\) is insoluble in water (\(\text{K}_{sp}\) of \(Mg(OH)_2 = 5.61\times10^{- 12}\)), so a precipitate (\(Mg(OH)_2\)) is formed.

Question 14

Write the molecular, complete ionic and net ionic equations:

• Molecular equation: \(H_2SO_4(aq)+2NaOH(aq)

ightarrow Na_2SO_4(aq)+2H_2O(l)\)

• Complete ionic equation: \(2H^{+}(aq)+SO_4^{2 -}(aq)+2Na^{+}(aq)+2OH^{-}(aq)

ightarrow 2Na^{+}(aq)+SO_4^{2 -}(aq)+2H_2O(l)\)

• Net ionic equation: We cancel out the spectator ions (\(Na^{+}\) and \(SO_4^{2 -}\)). The net ionic equation is \(H^{+}(aq)+OH^{-}(aq)

ightarrow H_2O(l)\)

Answer:

Question 13: \(KOH(aq)\) and \(Mg(NO_3)_2(aq)\)
Question 14: \(H^{+}(aq)+OH^{-}(aq)
ightarrow H_2O(l)\)