Question

question 13
factor the following trinomial.
$12a^2 - 17a - 5$
question help: message instructor
submit
question 14
factor the following trinomial.
$20a^2 - 41a + 20$
question help: message instructor
submit

Explanation:

Question 13:

Step1: Find pair for $12*(-5)$

We need two numbers that multiply to $12\times(-5)=-60$ and add to $-17$. The numbers are $-20$ and $3$.

Step2: Split middle term

$12a^2 - 20a + 3a - 5$

Step3: Group and factor pairs

$4a(3a - 5) + 1(3a - 5)$

Step4: Factor out common binomial

$(4a + 1)(3a - 5)$

Question 14:

Step1: Find pair for $20*20$

We need two numbers that multiply to $20\times20=400$ and add to $-41$. The numbers are $-16$ and $-25$.

Step2: Split middle term

$20a^2 - 16a - 25a + 20$

Step3: Group and factor pairs

$4a(5a - 4) - 5(5a - 4)$

Step4: Factor out common binomial

$(4a - 5)(5a - 4)$

Answer:

Question 13: $(4a + 1)(3a - 5)$
Question 14: $(4a - 5)(5a - 4)$