question 13

the atmospheric pressure at the summit of mt. kanchenjunga - the third highest mountain in the world - is around 455.0 torr.

calculate the volume, in liters, of a balloon at the top of kanchenjunga that has a volume of 11.5 liters at sea level, where the atmospheric pressure is 1.00 atm. assume the temperature differences are negligible.

Question

question 13

the atmospheric pressure at the summit of mt. kanchenjunga - the third highest mountain in the world - is around 455.0 torr.

calculate the volume, in liters, of a balloon at the top of kanchenjunga that has a volume of 11.5 liters at sea level, where the atmospheric pressure is 1.00 atm. assume the temperature differences are negligible.

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Pressure Unit Conversion" ], "new_concepts": [ "Boyles Law", "Gas Laws" ], "current_concepts": [ "Pressure Unit Conversion", "Boyles Law", "Gas Laws" ] } ## Convert pressure units to a common scale Using the **Pressure Unit Conversion** knowledge point $$ \begin{aligned} P_1 &= 1.00\text{ atm} = 760.0\text{ torr} \ P_2 &= 455.0\text{ torr} \end{aligned} $$ ## Apply Boyle's Law to find the final volume $$ \begin{aligned} P_1 V_1 &= P_2 V_2 \ V_2 &= \frac{P_1 V_1}{P_2} \ V_2 &= \frac{760.0\text{ torr} \times 11.5\text{ L}}{455.0\text{ torr}} \end{aligned} $$ ## Calculate the final numerical value $$ \begin{aligned} V_2 &= \frac{8740}{455.0}\text{ L} \ V_2 &\approx 19.2\text{ L} \end{aligned} $$ The atmospheric pressure at the summit of Mt. Kanchenjunga - the third highest mountain in the world - is around 455.0 torr. Calculate the volume, in liters, of a balloon at the top of Kanchenjunga that has a volume of 11.5 liters at sea level, where the atmospheric pressure is 1.00 atm. Assume the temperature differences are negligible. 19.2 { "subject": "Natural Science", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Natural Science", "Chemistry", "Gas Laws" ] }

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Question

Explanation:

Convert pressure units to a common scale

Apply Boyle's Law to find the final volume

Calculate the final numerical value

Answer: