Question

question 12 (2.5 points)
what is the volume and strength of a solution if 6 fl oz of isomil is added to 18 fl oz
of water?
24 fl oz ¼ strength
24 fl oz 1/3 strength
24 fl oz ½ strength
24 fl oz 2/3 strength
question 13 (2.5 points)
how many ml of hydrogen peroxide should be added to 320 ml of normal saline to
create 480 ml of 1/3 strength solution?
120 ml
140 ml
160 ml
200 ml
question 14 (2.5 points)
how much hydrogen peroxide is needed to prepare 16 fl oz of a 1/8 strength
solution?
1.0 fl oz
1.5 fl oz

Explanation:

Question 12

Step 1: Calculate Total Volume

Add the volume of Isomil and water: \( 6 + 18 = 24 \) fl oz.

Step 2: Calculate Strength

Strength is the ratio of Isomil to total solution: \( \frac{6}{24} = \frac{1}{4} \)? Wait, no, wait. Wait, Isomil is the solute? Wait, no, wait, maybe I messed up. Wait, 6 fl oz Isomil + 18 fl oz water. So the solute is Isomil, volume of solute is 6, total volume is 24. So strength is \( \frac{6}{24} = \frac{1}{4} \)? Wait, no, the options have 1/4, 1/3, etc. Wait, wait, maybe I made a mistake. Wait, 6 and 18: 6 is Isomil, 18 is water. So the solution is Isomil + water. So the strength is (volume of Isomil) / (total volume). So \( 6 / (6 + 18) = 6 / 24 = 1/4 \)? But wait, the options: first option is 24 fl oz 1/4 strength? Wait, no, the first option is "24 fl oz ¼ strength"? Wait, maybe the options are:

Option 1: 24 fl oz ¼ strength

Option 2: 24 fl oz 1/3 strength

Option 3: 24 fl oz ½ strength

Option 4: 24 fl oz 2/3 strength

Wait, let's recalculate. Wait, 6 fl oz Isomil + 18 fl oz water. Total volume is 24 fl oz. The strength is (Isomil volume) / (total volume) = 6/24 = 1/4. So the first option? Wait, but maybe I misread the options. Wait, the user's options:

First option: 24 fl oz ¼ strength

Second: 24 fl oz 1/3 strength

Third: 24 fl oz ½ strength

Fourth: 24 fl oz 2/3 strength

So the correct answer should be 24 fl oz 1/4 strength? Wait, but 6/24 is 1/4. So the first option.

Step 1: Let \( x \) be the volume of hydrogen peroxide.

Total volume is 480 mL, so \( x + 320 = 480 \)? No, wait, the solution is hydrogen peroxide + normal saline. The strength is 1/3, so (volume of hydrogen peroxide) / (total volume) = 1/3. Total volume is 480 mL, so volume of hydrogen peroxide is \( \frac{1}{3} \times 480 = 160 \) mL? But wait, normal saline is 320 mL. Wait, no, maybe the formula is: (volume of hydrogen peroxide) / (volume of hydrogen peroxide + volume of normal saline) = 1/3. Let \( x \) be volume of hydrogen peroxide. Then \( \frac{x}{x + 320} = \frac{1}{3} \). Cross-multiplying: \( 3x = x + 320 \) → \( 2x = 320 \) → \( x = 160 \) mL.

Step 2: Verify

Total volume: \( 160 + 320 = 480 \) mL. Strength: \( 160 / 480 = 1/3 \), which matches. So \( x = 160 \) mL.

Step 1: Let \( x \) be the volume of hydrogen peroxide.

Strength is 1/8, so \( \frac{x}{16} = \frac{1}{8} \). Solving for \( x \): \( x = 16 \times \frac{1}{8} = 2 \) fl oz? Wait, but the options are 1.0, 1.5, etc. Wait, maybe I misread the question. Wait, the question is "How much hydrogen peroxide is needed to prepare 16 fl oz of a 1/8 strength solution?" So strength is (volume of hydrogen peroxide) / (total volume) = 1/8. So \( x = 16 \times \frac{1}{8} = 2 \) fl oz. But the options given (partially shown) have 1.0, 1.5. Maybe there's a typo, but assuming the calculation: \( 16 \times \frac{1}{8} = 2 \), but if the options are 1.0, 1.5, maybe I made a mistake. Wait, maybe the strength is (hydrogen peroxide) / (water + hydrogen peroxide) = 1/8. Let total volume be 16, so hydrogen peroxide is \( x \), water is \( 16 - x \). Then \( \frac{x}{16} = \frac{1}{8} \) → \( x = 2 \). But the options don't have 2. Maybe the question was 1/8 strength, but maybe the total volume is different? Wait, maybe the user made a typo. But based on the formula, \( x = 16 \times \frac{1}{8} = 2 \) fl oz. But since the options given are 1.0, 1.5, maybe there's an error. Wait, maybe the question is 1/8 strength, but the total volume is different? Wait, no, the question says 16 fl oz. So according to the calculation, it's 2 fl oz. But since the options don't have 2, maybe I misread. Wait, maybe the strength is 1/16? No, the question says 1/8. Alternatively, maybe the solution is (hydrogen peroxide) / (water) = 1/8, but that's not standard. Standard strength is solute/total solution. So assuming standard, it's 2 fl oz. But since the options are 1.0, 1.5, maybe the question was 1/10 or something. But based on the given problem, the calculation is \( 16 \times \frac{1}{8} = 2 \) fl oz. But since the options don't have 2, maybe there's a mistake. However, following the formula, the answer should be 2 fl oz. But since the options given are 1.0, 1.5, etc., maybe the question was different. Wait, maybe the user made a typo. Alternatively, maybe I made a mistake. Wait, 16 fl oz total, 1/8 strength: 16 * 1/8 = 2. So the answer should be 2 fl oz, but since the options don't have that, maybe the question is different. But based on the given, the calculation is 2 fl oz.

Answer:

24 fl oz ¼ strength (assuming the first option is 24 fl oz ¼ strength)

Question 13