Question

question 11
5 pts
if the proportional limit for a structural material is 23,400 psi and its elastic limit occurs at 0.0023 in/in, compute the materials modulus of elasticity (e).
32,124.1 ksi
7,846.0 ksi
10,173.9 ksi
53.82 ksi
15,600.0 ksi

Explanation:

Step1: Recall modulus - of - elasticity formula

The formula for the modulus of elasticity $E=\frac{\sigma}{\epsilon}$, where $\sigma$ is the stress and $\epsilon$ is the strain.

Step2: Identify stress and strain values

The proportional limit is the maximum stress for which stress is proportional to strain. Here, $\sigma = 23400$ psi and $\epsilon=0.0023$ in/in.

Step3: Calculate modulus of elasticity

$E=\frac{23400}{0.0023}\text{ psi}=\frac{23400}{0.0023}\div1000\text{ ksi}\approx10173.9\text{ ksi}$

Answer:

10,173.9 ksi