Question

question 11 (1 point)
starting from rest, a 4.0-kg body reaches a speed of 8.0 m/s in 2.0 s. what is the net force acting on the body?
4.0 n
8.0 n
16 n
32 n
page 11 of 20

Explanation:

Step1: Find acceleration using kinematic formula

The formula for acceleration \(a\) is \(a=\frac{v - u}{t}\), where \(u = 0\) (starts from rest), \(v = 8.0\space m/s\), \(t = 2.0\space s\).
\(a=\frac{8.0 - 0}{2.0}=\frac{8.0}{2.0}=4.0\space m/s^{2}\)

Step2: Calculate net force using Newton's second law

Newton's second law is \(F = ma\), where \(m = 4.0\space kg\), \(a = 4.0\space m/s^{2}\).
\(F=4.0\times4.0 = 16\space N\)

Answer:

16 N (corresponding to the option "16 N")