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question 11 of 25 two water balloons of mass 0.75 kg collide and bounce…

Question

question 11 of 25
two water balloons of mass 0.75 kg collide and bounce off of each other without breaking. before the collision, one water balloon moved at a velocity of 3.5 m/s east, while the other moved at a velocity of 2.75 m/s west. after the collision, one balloon moves at a velocity of 1.5 m/s west. what is the velocity of the other water balloon?

a. 2.25 m/s east
b. 2.25 m/s west
c. 1.75 m/s east
d. 1.75 m/s west

Explanation:

Step1: Define Variables and Directions

Let east be positive and west be negative. Mass of each balloon \( m = 0.75 \, \text{kg} \). Initial velocities: \( v_{1i} = 3.5 \, \text{m/s} \) (east), \( v_{2i} = -2.75 \, \text{m/s} \) (west). Final velocity of one balloon: \( v_{2f} = -1.5 \, \text{m/s} \) (west). Let \( v_{1f} \) be the final velocity of the other balloon.

Step2: Apply Conservation of Momentum

Conservation of momentum: \( m v_{1i} + m v_{2i} = m v_{1f} + m v_{2f} \). Divide both sides by \( m \): \( v_{1i} + v_{2i} = v_{1f} + v_{2f} \).

Step3: Substitute Values and Solve

Substitute values: \( 3.5 + (-2.75) = v_{1f} + (-1.5) \). Calculate left side: \( 3.5 - 2.75 = 0.75 \). So, \( 0.75 = v_{1f} - 1.5 \). Add 1.5 to both sides: \( v_{1f} = 0.75 + 1.5 = 2.25 \, \text{m/s} \) (positive means east).

Answer:

A. 2.25 m/s east