Question

question 11 of 23 - multiple choice

the walls of a house are finished with 1\ x 8\ lap siding. if each course has 6-7/8\
exposed to the weather and there are 33 courses from the bottom to the top, what
is the height of the sided wall?

a 226-7/8\
b 173-1/4\
c 226-5/8\
d 264\

Explanation:

Identify the given values and target

Using the Lap Siding Calculation knowledge point, we identify:

• Exposed height per course: \(6\frac{7}{8}''\)
• Total number of courses: \(33\)
• Target: Total height of the sided wall

Calculate the total height

Using the Mixed Numbers Multiplication knowledge point

$$
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$$

Analyze the common misconception for Option B

We analyze why a student might incorrectly calculate \(173\frac{1}{4}''\) (Option B):

• If a student mistakenly uses the overlap or incorrect dimensions, such as subtracting the exposure from the nominal width: \(8 - 6\frac{7}{8} = 1\frac{1}{8}''\) overlap.
• If they multiply the overlap by the number of courses: \(33 \times 1\frac{1}{8} = 33 \times \frac{9}{8} = \frac{297}{8} = 37\frac{1}{8}''\).
• If they subtract this total overlap from the maximum un-overlapped height of \(33 \times 8'' = 264''\) (Option D):

$$ 264 - 37\frac{1}{8} = 226\frac{7}{8}'' \quad (\text{which is correct}) $$

• However, if they make an arithmetic error or use an incorrect exposure value like \(5\frac{1}{4}''\) instead:

$$ 33 \times 5\frac{1}{4} = 33 \times \frac{21}{4} = \frac{693}{4} = 173\frac{1}{4}'' $$

This shows Option B results from using an incorrect exposure of \(5\frac{1}{4}''\) per course.

Answer:

• A) 226-7/8" (Correct answer)
• B) 173-1/4"
• C) 226-5/8"
• D) 264"