Question

question 1 of 10
which shows the equation below written in the form $ax^2 + bx + c = 0$?
$x^2 + 7x + 9 = 3$

a. $x^2 + 4x + 6 = 0$
b. $x^2 + 7x + 12 = 0$
c. $x^2 + 4x + 12 = 0$
d. $x^2 + 7x + 6 = 0$

Explanation:

Step1: Subtract 3 from both sides

To convert \(x^{2}+7x + 9=3\) to the form \(ax^{2}+bx + c = 0\), we subtract 3 from both sides of the equation.
\(x^{2}+7x+9 - 3=3 - 3\)

Step2: Simplify the equation

Simplify the left - hand side and the right - hand side of the equation. The right - hand side \(3 - 3 = 0\), and the left - hand side \(x^{2}+7x+(9 - 3)=x^{2}+7x + 6\). So the equation becomes \(x^{2}+7x + 6=0\)

Answer:

D. \(x^{2}+7x + 6=0\)